/home/llmeval/.local/share/uv/tools/cubbi/lib/python3.12/site-packages/click/core.py:1213: UserWarning: The parameter -m is used more than once. Remove its duplicate as parameters should be unique. parser = self.make_parser(ctx) /home/llmeval/.local/share/uv/tools/cubbi/lib/python3.12/site-packages/click/core.py:1206: UserWarning: The parameter -m is used more than once. Remove its duplicate as parameters should be unique. self.parse_args(ctx, args) Using UID: 1000, GID: 1000 Forwarding environment variable OPENROUTER_API_KEY to container Mounting local directory /home/llmeval/llmeval/runs/run_20260118_150050/task14_graph_money_distribution/openrouter-google-gemini-2.5-flash-lite-preview-09-2025/workspace to /app No project_name provided - skipping configuration directory setup. Session created successfully! Session ID: 3ecb9188 Image: opencode Executing command and waiting for completion... Container will exit after command completes. Command logs: Initializing opencode v1.0.0 Setting up user 'cubbi' with UID: 1000, GID: 1000 Setting up standard directories Created directory: /app Created directory: /cubbi-config Created directory: /cubbi-config/home Creating /home/cubbi as symlink to /cubbi-config/home Created directory: /cubbi-config/home/.local Copied /root/.local/bin to user directory Running opencode-specific initialization Added litellm custom provider with 157 models to OpenCode configuration Added openrouter standard provider with 339 models to OpenCode configuration Set default model to openrouter/google/gemini-2.5-flash-lite-preview-09-2025 Updated OpenCode configuration at /home/cubbi/.config/opencode/config.json with 2 providers No MCP servers to integrate --- Executing initial command --- Executing user command: if [ -f install.sh ]; then bash install.sh; fi; echo "--- TASK BEGIN ---"; cat task.md; echo "--- TASK END ---"; cd input && opencode run --print-logs < ../task.md Executing as cubbi: sh -c if [ -f install.sh ]; then bash install.sh; fi; echo "--- TASK BEGIN ---"; cat task.md; echo "--- TASK END ---"; cd input && opencode run --print-logs < ../task.md --- TASK BEGIN --- # Deterministic Money Distribution on a Directed Graph You must compute the final money distribution on a directed graph following precise rules. ## Graph Structure **CONDUCTOR nodes**: C1 through C10 **BENEFICIARY nodes**: B1 through B10 (each Ci has exactly one Bi) **Directed edges between CONDUCTORs**: ``` C1 --> C2 C2 --> C3 C3 --> C4 C4 --> C2 C4 --> C5 C5 --> C6 C6 --> C7 C7 --> C5 C7 --> C8 C8 --> C9 C9 --> C10 C10 --> C6 ``` ## Initial Conditions Solve for **three scenarios**: 1. **Scenario A**: C4 receives **5 cents**. All other nodes start with 0 cents. 2. **Scenario B**: C4 receives **50 cents**. All other nodes start with 0 cents. 3. **Scenario C**: C4 receives **100 cents**. All other nodes start with 0 cents. ## Distribution Rules When a CONDUCTOR Ci receives N > 0 cents, it distributes ALL N cents in a single step to: - Its BENEFICIARY Bi - All CONDUCTORs it has outgoing edges to **Split Rule**: 1. Divide money equally among all participants 2. Remaining cents (from integer division) are distributed one by one 3. **Tie-break order**: BENEFICIARY first, then CONDUCTORs alphabetically (C1 < C2 < ... < C10) **Example**: 8 cents split among [B4, C2, C5]: - 8 / 3 = 2 each, remainder = 2 - Distribution order: B4, C2, C5 - Final: B4=3, C2=3, C5=2 ## Recursion Any CONDUCTOR receiving positive money repeats the same distribution. BENEFICIARY nodes absorb money and never redistribute. ## Termination Process ends when no CONDUCTOR holds positive money. ## Your Task Compute the final amount held by each BENEFICIARY after the process terminates, for all three scenarios. ## Required Output Create three files: **`result_5.json`** (for Scenario A - 5 cents): ```json { "B1": , "B2": , "B3": , "B4": , "B5": , "B6": , "B7": , "B8": , "B9": , "B10": } ``` **`result_50.json`** (for Scenario B - 50 cents): ```json { "B1": , "B2": , "B3": , "B4": , "B5": , "B6": , "B7": , "B8": , "B9": , "B10": } ``` **`result_100.json`** (for Scenario C - 100 cents): ```json { "B1": , "B2": , "B3": , "B4": , "B5": , "B6": , "B7": , "B8": , "B9": , "B10": } ``` PS: You are currently working in an automated system and cannot ask any question or have back and forth with a user. --- TASK END --- INFO 2026-01-18T15:34:52 +860ms service=default version=1.1.17 args=["run","--print-logs"] opencode INFO 2026-01-18T15:34:52 +3ms service=default directory=/app/input creating instance INFO 2026-01-18T15:34:52 +0ms service=project directory=/app/input fromDirectory INFO 2026-01-18T15:34:52 +10ms service=storage index=0 running migration ERROR 2026-01-18T15:34:52 +11ms service=storage index=0 failed to run migration INFO 2026-01-18T15:34:52 +0ms service=storage index=1 running migration INFO 2026-01-18T15:34:52 +14ms service=default directory=/app/input bootstrapping INFO 2026-01-18T15:34:52 +20ms service=config path=/home/cubbi/.config/opencode/config.json loading INFO 2026-01-18T15:34:52 +82ms service=config path=/home/cubbi/.config/opencode/opencode.json loading INFO 2026-01-18T15:34:52 +1ms service=config path=/home/cubbi/.config/opencode/opencode.jsonc loading INFO 2026-01-18T15:34:52 +14ms service=bun cmd=["/opt/node/lib/node_modules/opencode-ai/node_modules/opencode-linux-x64/bin/opencode","add","@opencode-ai/plugin@1.1.17","--exact"] cwd=/home/cubbi/.config/opencode running INFO 2026-01-18T15:34:53 +678ms service=bun code=0 stdout=bun add v1.3.5 (1e86cebd) installed @opencode-ai/plugin@1.1.17 3 packages installed [645.00ms] stderr=Resolving dependencies Resolved, downloaded and extracted [12] Saved lockfile done INFO 2026-01-18T15:34:53 +0ms service=bun cmd=["/opt/node/lib/node_modules/opencode-ai/node_modules/opencode-linux-x64/bin/opencode","install"] cwd=/home/cubbi/.config/opencode running INFO 2026-01-18T15:34:53 +20ms service=bun code=0 stdout=bun install v1.3.5 (1e86cebd) Checked 3 installs across 4 packages (no changes) [7.00ms] stderr= done INFO 2026-01-18T15:34:53 +19ms service=plugin name=CodexAuthPlugin loading internal plugin INFO 2026-01-18T15:34:53 +0ms service=plugin path=opencode-copilot-auth@0.0.12 loading plugin INFO 2026-01-18T15:34:53 +10ms service=bun pkg=opencode-copilot-auth version=0.0.12 installing package using Bun's default registry resolution INFO 2026-01-18T15:34:53 +0ms service=bun cmd=["/opt/node/lib/node_modules/opencode-ai/node_modules/opencode-linux-x64/bin/opencode","add","--force","--exact","--cwd","/home/cubbi/.cache/opencode","opencode-copilot-auth@0.0.12"] cwd=/home/cubbi/.cache/opencode running INFO 2026-01-18T15:34:53 +172ms service=bun code=0 stdout=bun add v1.3.5 (1e86cebd) installed opencode-copilot-auth@0.0.12 1 package installed [161.00ms] stderr=Resolving dependencies Resolved, downloaded and extracted [4] Saved lockfile done INFO 2026-01-18T15:34:53 +5ms service=plugin path=opencode-anthropic-auth@0.0.8 loading plugin INFO 2026-01-18T15:34:53 +1ms service=bun pkg=opencode-anthropic-auth version=0.0.8 installing package using Bun's default registry resolution INFO 2026-01-18T15:34:53 +0ms service=bun cmd=["/opt/node/lib/node_modules/opencode-ai/node_modules/opencode-linux-x64/bin/opencode","add","--force","--exact","--cwd","/home/cubbi/.cache/opencode","opencode-anthropic-auth@0.0.8"] cwd=/home/cubbi/.cache/opencode running INFO 2026-01-18T15:34:54 +633ms service=bun code=0 stdout=bun add v1.3.5 (1e86cebd) + opencode-copilot-auth@0.0.12 installed opencode-anthropic-auth@0.0.8 14 packages installed [613.00ms] stderr=Resolving dependencies Resolved, downloaded and extracted [50] Saved lockfile done INFO 2026-01-18T15:34:54 +71ms service=bus type=* subscribing INFO 2026-01-18T15:34:54 +0ms service=bus type=session.updated subscribing INFO 2026-01-18T15:34:54 +0ms service=bus type=message.updated subscribing INFO 2026-01-18T15:34:54 +1ms service=bus type=message.part.updated subscribing INFO 2026-01-18T15:34:54 +0ms service=bus type=session.updated subscribing INFO 2026-01-18T15:34:54 +0ms service=bus type=message.updated subscribing INFO 2026-01-18T15:34:54 +0ms service=bus type=message.part.updated subscribing INFO 2026-01-18T15:34:54 +0ms service=bus type=session.diff subscribing INFO 2026-01-18T15:34:54 +0ms service=format init INFO 2026-01-18T15:34:54 +0ms service=bus type=file.edited subscribing INFO 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INFO 2026-01-18T15:35:36 +57ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +73ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +76ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +66ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +70ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +87ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +59ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +67ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +102ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +44ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +67ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +72ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +68ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +56ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:37 +103ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:38 +75ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:38 +87ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:38 +452ms service=bus type=message.part.updated publishing This is a complex simulation problem that requires carefully tracking state transitions based on graph traversal and specific division/remainder rules. Since I cannot ask questions and must deliver the final files, I will use a simulation approach. First, I will analyze the graph structure and the distribution rules to determine the cycles and the tie-breaking order for distribution. ### 1. Graph and Node Setup **Conductors (C1-C10):** Initial money $M_C = \{C_i: 0\}$ for all $i$, except for the starting node in each scenario. **Beneficiaries (B1-B10):** Initial money $M_B = \{B_i: 0\}$ for all $i$. **Graph Edges (Outgoing from C_i):** * C1 -> {C2} * C2 -> {C3} * C3 -> {C4} * C4 -> {C2, C5} * C5 -> {C6} * C6 -> {C7} * C7 -> {C5, C8} * C8 -> {C9} * C9 -> {C10} * C10 -> {C6} **Recurrent Cycles:** 1. $C2 \to C3 \to C4 \to C2$ (Cycle of length 3) 2. $C5 \to C6 \to C7 \to C5$ (Cycle of length 3) 3. $C6 \to C7 \to C8 \to C9 \to C10 \to C6$ (Cycle of length 5, containing C6, C7) The structure is: $$C1 \to C2 \leftrightarrow C3 \leftrightarrow C4 \to C5 \leftrightarrow C6 \leftrightarrow C7 \leftrightarrow C8 \to C9 \to C10 \to C6$$ And $C4$ connects to $C5$, which starts the second major cycle. **Termination Condition:** The process terminates when no conductor holds positive money. Since the distribution rules always move money out of a conductor (either to its beneficiary or to outgoing conductors), and money is only added to conductors from other conductors, if the graph contained no cycles, it would terminate. However, the graph **contains cycles** ($C2-C3-C4$, $C5-C6-C7$), meaning money could flow indefinitely *unless* the distribution rules cause all conductors in the cycle to eventually pass all their received money to their respective beneficiaries. Let's analyze the distribution target sets. ### 2. Distribution Rule & Tie-break Order When $C_i$ has $N$ cents, the set of recipients $R_i$ is: $$R_i = \{B_i\} \cup \{\text{outgoing conductors from } C_i\}$$ The size of the recipient set is $|R_i| = 1 + |\text{outgoing conductors}|$. **Recipient Sets $R_i$ and Distribution Sizes:** | Conductor $C_i$ | Outgoing To | Recipients $R_i$ (Order for remainder) | $|R_i|$ | Tie-break Order (B first, then C alphabetical) | | :---: | :---: | :--- | :---: | :--- | | C1 | {C2} | {B1, C2} | 2 | B1, C2 | | C2 | {C3} | {B2, C3} | 2 | B2, C3 | | C3 | {C4} | {B3, C4} | 2 | B3, C4 | | C4 | {C2, C5} | {B4, C2, C5} | 3 | B4, C2, C5 | | C5 | {C6} | {B5, C6} | 2 | B5, C6 | | C6 | {C7} | {B6, C7} | 2 | B6, C7 | | C7 | {C5, C8} | {B7, C5, C8} | 3 | B7, C5, C8 | | C8 | {C9} | {B8, C9} | 2 | B8, C9 | | C9 | {C10} | {B9, C10} | 2 | B9, C10 | | C10 | {C6} | {B10, C6} | 2 | B10, C6 | **Distribution Calculation for $N$ cents among $|R|$ recipients:** * Base amount per recipient: $Q = \lfloor N / |R| \rfloor$ * Remainder: $R = N \pmod{|R|}$ * The first $R$ recipients in the tie-break order receive $Q+1$. * The remaining $|R|-R$ recipients receive $Q$. Since the remainder distribution favors beneficiaries and lower-indexed conductors, money tends to move towards $B_i$ as it propagates. **The process must terminate** because in every distribution step, at least one conductor passes its money *out* to its beneficiary, who absorbs it permanently. In a finite system, this guarantees termination. ### 3. Simulation Execution We will simulate the process step-by-step for each scenario using a queue of pending conductor amounts. Initial state: $M_C = \{C_i: 0\}$, $M_B = \{B_i: 0\}$. --- ## Scenario A: C4 receives 5 cents. Initial Pending: $P = \{(C4, 5)\}$ **Step 1:** Process (C4, 5). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = \lfloor 5/3 \rfloor = 1$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets $1+1=2$. C2 gets $1+1=2$. C5 gets $1$. * $M_B$: $B4 = 2$. * New Pending: $P = \{(C2, 2), (C5, 1)\}$. **Step 2:** Process (C2, 2). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = \lfloor 2/2 \rfloor = 1$. Remainder $R = 0$. * B2 gets 1. C3 gets 1. * $M_B$: $B4 = 2, B2 = 1$. * New Pending: $P = \{(C5, 1), (C3, 1)\}$. **Step 3:** Process (C5, 1). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = \lfloor 1/2 \rfloor = 0$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets $0+1=1$. C6 gets $0$. * $M_B$: $B4 = 2, B2 = 1, B5 = 1$. * New Pending: $P = \{(C3, 1)\}$. (C6 gets 0, so it is not added) **Step 4:** Process (C3, 1). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = \lfloor 1/2 \rfloor = 0$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets $0+1=1$. C4 gets $0$. * $M_B$: $B4 = 2, B2 = 1, B5 = 1, B3 = 1$. * New Pending: $P = \{\}$. (C4 gets 0, so it is not added) **Termination.** **Scenario A Final Beneficiary Amounts:** * B1: 0 * B2: 1 * B3: 1 * B4: 2 * B5: 1 * B6-B10: 0 --- ## Scenario B: C4 receives 50 cents. Initial Pending: $P = \{(C4, 50)\}$ **Step 1:** Process (C4, 50). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = \lfloor 50/3 \rfloor = 16$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets $16+1=17$. C2 gets $16+1=17$. C5 gets $16$. * $M_B$: $B4 = 17$. * New Pending: $P = \{(C2, 17), (C5, 16)\}$. **Step 2:** Process (C2, 17). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = \lfloor 17/2 \rfloor = 8$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets $8+1=9$. C3 gets $8$. * $M_B$: $B4 = 17, B2 = 9$. * New Pending: $P = \{(C5, 16), (C3, 8)\}$. **Step 3:** Process (C5, 16). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = \lfloor 16/2 \rfloor = 8$. Remainder $R = 0$. * B5 gets 8. C6 gets 8. * $M_B$: $B4 = 17, B2 = 9, B5 = 8$. * New Pending: $P = \{(C3, 8), (C6, 8)\}$. **Step 4:** Process (C3, 8). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = \lfloor 8/2 \rfloor = 4$. Remainder $R = 0$. * B3 gets 4. C4 gets 4. * $M_B$: $B4 = 17, B2 = 9, B5 = 8, B3 = 4$. * New Pending: $P = \{(C6, 8), (C4, 4)\}$. **Step 5:** Process (C6, 8). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = \lfloor 8/2 \rfloor = 4$. Remainder $R = 0$. * B6 gets 4. C7 gets 4. * $M_B$: $B4=17, B2=9, B5=8, B3=4, B6=4$. * New Pending: $P = \{(C4, 4), (C7, 4)\}$. **Step 6:** Process (C4, 4). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = \lfloor 4/3 \rfloor = 1$. Remainder $R = 1$. * Tie-break order: B4, C2, C5. * B4 gets $1+1=2$. C2 gets $1$. C5 gets $1$. * $M_B$: $B4 = 17+2 = 19$. * New Pending: $P = \{(C7, 4), (C2, 1), (C5, 1)\}$. **Step 7:** Process (C7, 4). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = \lfloor 4/3 \rfloor = 1$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets $1+1=2$. C5 gets $1$. C8 gets $1$. * $M_B$: $B4=19, B2=9, B5=8+1=9, B3=4, B6=4, B7=2$. * New Pending: $P = \{(C2, 1), (C5, 1+1=2), (C8, 1)\}$. (C5 got 1 from Step 6, plus 1 from Step 7) **Step 8:** Process (C2, 1). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = \lfloor 1/2 \rfloor = 0$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets $0+1=1$. C3 gets $0$. * $M_B$: $B2 = 9+1 = 10$. * New Pending: $P = \{(C5, 2), (C8, 1)\}$. (C3 gets 0) **Step 9:** Process (C5, 2). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = \lfloor 2/2 \rfloor = 1$. Remainder $R = 0$. * B5 gets 1. C6 gets 1. * $M_B$: $B5 = 9+1 = 10$. * New Pending: $P = \{(C8, 1), (C6, 1)\}$. **Step 10:** Process (C8, 1). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = \lfloor 1/2 \rfloor = 0$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets $0+1=1$. C9 gets $0$. * $M_B$: $B8 = 1$. * New Pending: $P = \{(C6, 1)\}$. (C9 gets 0) **Step 11:** Process (C6, 1). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = \lfloor 1/2 \rfloor = 0$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets $0+1=1$. C7 gets $0$. * $M_B$: $B6 = 4+1 = 5$. * New Pending: $P = \{\}$. (C7 gets 0) **Termination.** **Scenario B Final Beneficiary Amounts:** * B1: 0 * B2: 10 * B3: 4 * B4: 19 * B5: 10 * B6: 5 * B7: 2 * B8: 1 * B9: 0 * B10: 0 --- ## Scenario C: C4 receives 100 cents. Initial Pending: $P = \{(C4, 100)\}$ **Step 1:** Process (C4, 100). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = \lfloor 100/3 \rfloor = 33$. Remainder $R = 1$. * Tie-break order: B4, C2, C5. * B4 gets 34. C2 gets 33. C5 gets 33. * $M_B$: $B4 = 34$. * New Pending: $P = \{(C2, 33), (C5, 33)\}$. **Step 2:** Process (C2, 33). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = \lfloor 33/2 \rfloor = 16$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 17. C3 gets 16. * $M_B$: $B4 = 34, B2 = 17$. * New Pending: $P = \{(C5, 33), (C3, 16)\}$. **Step 3:** Process (C5, 33). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = \lfloor 33/2 \rfloor = 16$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 17. C6 gets 16. * $M_B$: $B4 = 34, B2 = 17, B5 = 17$. * New Pending: $P = \{(C3, 16), (C6, 16)\}$. **Step 4:** Process (C3, 16). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = \lfloor 16/2 \rfloor = 8$. Remainder $R = 0$. * B3 gets 8. C4 gets 8. * $M_B$: $B4 = 34, B2 = 17, B5 = 17, B3 = 8$. * New Pending: $P = \{(C6, 16), (C4, 8)\}$. **Step 5:** Process (C6, 16). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = \lfloor 16/2 \rfloor = 8$. Remainder $R = 0$. * B6 gets 8. C7 gets 8. * $M_B$: $B4 = 34, B2 = 17, B5 = 17, B3 = 8, B6 = 8$. * New Pending: $P = \{(C4, 8), (C7, 8)\}$. **Step 6:** Process (C4, 8). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = \lfloor 8/3 \rfloor = 2$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 3. C2 gets 3. C5 gets 2. * $M_B$: $B4 = 34+3 = 37$. * New Pending: $P = \{(C7, 8), (C2, 33+3=36), (C5, 33+2=35)\}$. **Step 7:** Process (C7, 8). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = \lfloor 8/3 \rfloor = 2$. Remainder $R = 2$. * Tie-break order: B7, C5, C8. * B7 gets 3. C5 gets 3. C8 gets 2. * $M_B$: $B7 = 3$. * New Pending: $P = \{(C2, 36), (C5, 35+3=38), (C8, 2)\}$. **Step 8:** Process (C2, 36). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 18$. Remainder $R = 0$. * B2 gets 18. C3 gets 18. * $M_B$: $B2 = 17+18 = 35$. * New Pending: $P = \{(C5, 38), (C8, 2), (C3, 16+18=34)\}$. **Step 9:** Process (C5, 38). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 19$. Remainder $R = 0$. * B5 gets 19. C6 gets 19. * $M_B$: $B5 = 17+19 = 36$. * New Pending: $P = \{(C8, 2), (C3, 34), (C6, 16+19=35)\}$. **Step 10:** Process (C8, 2). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 1$. Remainder $R = 0$. * B8 gets 1. C9 gets 1. * $M_B$: $B8 = 1$. * New Pending: $P = \{(C3, 34), (C6, 35), (C9, 1)\}$. **Step 11:** Process (C3, 34). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 17$. Remainder $R = 0$. * B3 gets 17. C4 gets 17. * $M_B$: $B3 = 8+17 = 25$. * New Pending: $P = \{(C6, 35), (C9, 1), (C4, 17)\}$. **Step 12:** Process (C6, 35). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 17$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 18. C7 gets 17. * $M_B$: $B6 = 8+18 = 26$. * New Pending: $P = \{(C9, 1), (C4, 17), (C7, 8+17=25)\}$. **Step 13:** Process (C9, 1). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 0$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 1. C10 gets 0. * $M_B$: $B9 = 1$. * New Pending: $P = \{(C4, 17), (C7, 25)\}$. (C10 gets 0) **Step 14:** Process (C4, 17). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 5$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 6. C2 gets 6. C5 gets 5. * $M_B$: $B4 = 37+6 = 43$. * New Pending: $P = \{(C7, 25), (C2, 36+6=42), (C5, 38+5=43)\}$. **Step 15:** Process (C7, 25). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 8$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 9. C5 gets 8. C8 gets 8. * $M_B$: $B7 = 3+9 = 12$. * New Pending: $P = \{(C2, 42), (C5, 43+8=51), (C8, 1+8=9)\}$. **Step 16:** Process (C2, 42). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 21$. Remainder $R = 0$. * B2 gets 21. C3 gets 21. * $M_B$: $B2 = 35+21 = 56$. * New Pending: $P = \{(C5, 51), (C8, 9), (C3, 34+21=55)\}$. **Step 17:** Process (C5, 51). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 25$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 26. C6 gets 25. * $M_B$: $B5 = 36+26 = 62$. * New Pending: $P = \{(C8, 9), (C3, 55), (C6, 35+25=60)\}$. **Step 18:** Process (C8, 9). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 4$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 5. C9 gets 4. * $M_B$: $B8 = 1+5 = 6$. * New Pending: $P = \{(C3, 55), (C6, 60), (C9, 1+4=5)\}$. **Step 19:** Process (C3, 55). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 27$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 28. C4 gets 27. * $M_B$: $B3 = 25+28 = 53$. * New Pending: $P = \{(C6, 60), (C9, 5), (C4, 17+27=44)\}$. **Step 20:** Process (C6, 60). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 30$. Remainder $R = 0$. * B6 gets 30. C7 gets 30. * $M_B$: $B6 = 26+30 = 56$. * New Pending: $P = \{(C9, 5), (C4, 44), (C7, 25+30=55)\}$. **Step 21:** Process (C9, 5). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 2$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 3. C10 gets 2. * $M_B$: $B9 = 1+3 = 4$. * New Pending: $P = \{(C4, 44), (C7, 55), (C10, 2)\}$. **Step 22:** Process (C4, 44). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 14$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 15. C2 gets 15. C5 gets 14. * $M_B$: $B4 = 43+15 = 58$. * New Pending: $P = \{(C7, 55), (C2, 42+15=57), (C5, 51+14=65)\}$. **Step 23:** Process (C7, 55). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 18$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 19. C5 gets 18. C8 gets 18. * $M_B$: $B7 = 12+19 = 31$. * New Pending: $P = \{(C2, 57), (C5, 65+18=83), (C8, 9+18=27)\}$. **Step 24:** Process (C2, 57). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 28$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 29. C3 gets 28. * $M_B$: $B2 = 56+29 = 85$. * New Pending: $P = \{(C5, 83), (C8, 27), (C3, 55+28=83)\}$. **Step 25:** Process (C5, 83). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 41$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 42. C6 gets 41. * $M_B$: $B5 = 62+42 = 104$. * New Pending: $P = \{(C8, 27), (C3, 83), (C6, 60+41=101)\}$. **Step 26:** Process (C8, 27). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 13$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 14. C9 gets 13. * $M_B$: $B8 = 6+14 = 20$. * New Pending: $P = \{(C3, 83), (C6, 101), (C9, 5+13=18)\}$. **Step 27:** Process (C3, 83). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 41$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 42. C4 gets 41. * $M_B$: $B3 = 53+42 = 95$. * New Pending: $P = \{(C6, 101), (C9, 18), (C4, 44+41=85)\}$. **Step 28:** Process (C6, 101). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 50$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 51. C7 gets 50. * $M_B$: $B6 = 56+51 = 107$. * New Pending: $P = \{(C9, 18), (C4, 85), (C7, 55+50=105)\}$. **Step 29:** Process (C9, 18). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 9$. Remainder $R = 0$. * B9 gets 9. C10 gets 9. * $M_B$: $B9 = 4+9 = 13$. * New Pending: $P = \{(C4, 85), (C7, 105), (C10, 2+9=11)\}$. **Step 30:** Process (C4, 85). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 28$. Remainder $R = 1$. * Tie-break order: B4, C2, C5. * B4 gets 29. C2 gets 28. C5 gets 28. * $M_B$: $B4 = 58+29 = 87$. * New Pending: $P = \{(C7, 105), (C2, 57+28=85), (C5, 83+28=111)\}$. **Step 31:** Process (C7, 105). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 35$. Remainder $R = 0$. * B7 gets 35. C5 gets 35. C8 gets 35. * $M_B$: $B7 = 31+35 = 66$. * New Pending: $P = \{(C2, 85), (C5, 111+35=146), (C8, 27+35=62)\}$. **Step 32:** Process (C2, 85). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 42$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 43. C3 gets 42. * $M_B$: $B2 = 85+43 = 128$. * New Pending: $P = \{(C5, 146), (C8, 62), (C3, 83+42=125)\}$. **Step 33:** Process (C5, 146). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 73$. Remainder $R = 0$. * B5 gets 73. C6 gets 73. * $M_B$: $B5 = 104+73 = 177$. * New Pending: $P = \{(C8, 62), (C3, 125), (C6, 101+73=174)\}$. **Step 34:** Process (C8, 62). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 31$. Remainder $R = 0$. * B8 gets 31. C9 gets 31. * $M_B$: $B8 = 20+31 = 51$. * New Pending: $P = \{(C3, 125), (C6, 174), (C9, 18+31=49)\}$. **Step 35:** Process (C3, 125). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 62$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 63. C4 gets 62. * $M_B$: $B3 = 95+63 = 158$. * New Pending: $P = \{(C6, 174), (C9, 49), (C4, 85+62=147)\}$. **Step 36:** Process (C6, 174). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 87$. Remainder $R = 0$. * B6 gets 87. C7 gets 87. * $M_B$: $B6 = 107+87 = 194$. * New Pending: $P = \{(C9, 49), (C4, 147), (C7, 105+87=192)\}$. **Step 37:** Process (C9, 49). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 24$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 25. C10 gets 24. * $M_B$: $B9 = 13+25 = 38$. * New Pending: $P = \{(C4, 147), (C7, 192), (C10, 11+24=35)\}$. **Step 38:** Process (C4, 147). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 49$. Remainder $R = 0$. * B4 gets 49. C2 gets 49. C5 gets 49. * $M_B$: $B4 = 87+49 = 136$. * New Pending: $P = \{(C7, 192), (C2, 85+49=134), (C5, 146+49=195)\}$. **Step 39:** Process (C7, 192). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 64$. Remainder $R = 0$. * B7 gets 64. C5 gets 64. C8 gets 64. * $M_B$: $B7 = 66+64 = 130$. * New Pending: $P = \{(C2, 134), (C5, 195+64=259), (C8, 62+64=126)\}$. **Step 40:** Process (C2, 134). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 67$. Remainder $R = 0$. * B2 gets 67. C3 gets 67. * $M_B$: $B2 = 128+67 = 195$. * New Pending: $P = \{(C5, 259), (C8, 126), (C3, 125+67=192)\}$. **Step 41:** Process (C5, 259). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 129$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 130. C6 gets 129. * $M_B$: $B5 = 177+130 = 307$. * New Pending: $P = \{(C8, 126), (C3, 192), (C6, 174+129=303)\}$. **Step 42:** Process (C8, 126). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 63$. Remainder $R = 0$. * B8 gets 63. C9 gets 63. * $M_B$: $B8 = 51+63 = 114$. * New Pending: $P = \{(C3, 192), (C6, 303), (C9, 49+63=112)\}$. **Step 43:** Process (C3, 192). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 96$. Remainder $R = 0$. * B3 gets 96. C4 gets 96. * $M_B$: $B3 = 158+96 = 254$. * New Pending: $P = \{(C6, 303), (C9, 112), (C4, 147+96=243)\}$. **Step 44:** Process (C6, 303). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 151$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 152. C7 gets 151. * $M_B$: $B6 = 194+152 = 346$. * New Pending: $P = \{(C9, 112), (C4, 243), (C7, 192+151=343)\}$. **Step 45:** Process (C9, 112). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 56$. Remainder $R = 0$. * B9 gets 56. C10 gets 56. * $M_B$: $B9 = 38+56 = 94$. * New Pending: $P = \{(C4, 243), (C7, 343), (C10, 35+56=91)\}$. **Step 46:** Process (C4, 243). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 81$. Remainder $R = 0$. * B4 gets 81. C2 gets 81. C5 gets 81. * $M_B$: $B4 = 136+81 = 217$. * New Pending: $P = \{(C7, 343), (C2, 134+81=215), (C5, 195+81=276)\}$. **Step 47:** Process (C7, 343). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 114$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 115. C5 gets 114. C8 gets 114. * $M_B$: $B7 = 130+115 = 245$. * New Pending: $P = \{(C2, 215), (C5, 276+114=390), (C8, 126+114=240)\}$. **Step 48:** Process (C2, 215). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 107$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 108. C3 gets 107. * $M_B$: $B2 = 195+108 = 303$. * New Pending: $P = \{(C5, 390), (C8, 240), (C3, 192+107=299)\}$. **Step 49:** Process (C5, 390). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 195$. Remainder $R = 0$. * B5 gets 195. C6 gets 195. * $M_B$: $B5 = 307+195 = 502$. * New Pending: $P = \{(C8, 240), (C3, 299), (C6, 303+195=498)\}$. **Step 50:** Process (C8, 240). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 120$. Remainder $R = 0$. * B8 gets 120. C9 gets 120. * $M_B$: $B8 = 114+120 = 234$. * New Pending: $P = \{(C3, 299), (C6, 498), (C9, 112+120=232)\}$. **Step 51:** Process (C3, 299). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 149$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 150. C4 gets 149. * $M_B$: $B3 = 254+150 = 404$. * New Pending: $P = \{(C6, 498), (C9, 232), (C4, 243+149=392)\}$. **Step 52:** Process (C6, 498). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 249$. Remainder $R = 0$. * B6 gets 249. C7 gets 249. * $M_B$: $B6 = 346+249 = 595$. * New Pending: $P = \{(C9, 232), (C4, 392), (C7, 343+249=592)\}$. **Step 53:** Process (C9, 232). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 116$. Remainder $R = 0$. * B9 gets 116. C10 gets 116. * $M_B$: $B9 = 94+116 = 210$. * New Pending: $P = \{(C4, 392), (C7, 592), (C10, 91+116=207)\}$. **Step 54:** Process (C4, 392). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 130$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 131. C2 gets 131. C5 gets 130. * $M_B$: $B4 = 217+131 = 348$. * New Pending: $P = \{(C7, 592), (C2, 215+131=346), (C5, 390+130=520)\}$. **Step 55:** Process (C7, 592). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 197$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 198. C5 gets 197. C8 gets 197. * $M_B$: $B7 = 245+198 = 443$. * New Pending: $P = \{(C2, 346), (C5, 520+197=717), (C8, 240+197=437)\}$. **Step 56:** Process (C2, 346). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 173$. Remainder $R = 0$. * B2 gets 173. C3 gets 173. * $M_B$: $B2 = 303+173 = 476$. * New Pending: $P = \{(C5, 717), (C8, 437), (C3, 299+173=472)\}$. **Step 57:** Process (C5, 717). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 358$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 359. C6 gets 358. * $M_B$: $B5 = 502+359 = 861$. * New Pending: $P = \{(C8, 437), (C3, 472), (C6, 498+358=856)\}$. **Step 58:** Process (C8, 437). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 218$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 219. C9 gets 218. * $M_B$: $B8 = 234+219 = 453$. * New Pending: $P = \{(C3, 472), (C6, 856), (C9, 232+218=450)\}$. **Step 59:** Process (C3, 472). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 236$. Remainder $R = 0$. * B3 gets 236. C4 gets 236. * $M_B$: $B3 = 404+236 = 640$. * New Pending: $P = \{(C6, 856), (C9, 450), (C4, 392+236=628)\}$. **Step 60:** Process (C6, 856). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 428$. Remainder $R = 0$. * B6 gets 428. C7 gets 428. * $M_B$: $B6 = 595+428 = 1023$. * New Pending: $P = \{(C9, 450), (C4, 628), (C7, 592+428=1020)\}$. **Step 61:** Process (C9, 450). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 225$. Remainder $R = 0$. * B9 gets 225. C10 gets 225. * $M_B$: $B9 = 210+225 = 435$. * New Pending: $P = \{(C4, 628), (C7, 1020), (C10, 207+225=432)\}$. **Step 62:** Process (C4, 628). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 209$. Remainder $R = 1$. * Tie-break order: B4, C2, C5. * B4 gets 210. C2 gets 209. C5 gets 209. * $M_B$: $B4 = 348+210 = 558$. * New Pending: $P = \{(C7, 1020), (C2, 346+209=555), (C5, 717+209=926)\}$. **Step 63:** Process (C7, 1020). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 340$. Remainder $R = 0$. * B7 gets 340. C5 gets 340. C8 gets 340. * $M_B$: $B7 = 443+340 = 783$. * New Pending: $P = \{(C2, 555), (C5, 926+340=1266), (C8, 437+340=777)\}$. **Step 64:** Process (C2, 555). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 277$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 278. C3 gets 277. * $M_B$: $B2 = 476+278 = 754$. * New Pending: $P = \{(C5, 1266), (C8, 777), (C3, 472+277=749)\}$. **Step 65:** Process (C5, 1266). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 633$. Remainder $R = 0$. * B5 gets 633. C6 gets 633. * $M_B$: $B5 = 861+633 = 1494$. * New Pending: $P = \{(C8, 777), (C3, 749), (C6, 856+633=1489)\}$. **Step 66:** Process (C8, 777). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 388$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 389. C9 gets 388. * $M_B$: $B8 = 453+389 = 842$. * New Pending: $P = \{(C3, 749), (C6, 1489), (C9, 450+388=838)\}$. **Step 67:** Process (C3, 749). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 374$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 375. C4 gets 374. * $M_B$: $B3 = 640+375 = 1015$. * New Pending: $P = \{(C6, 1489), (C9, 838), (C4, 628+374=1002)\}$. **Step 68:** Process (C6, 1489). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 744$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 745. C7 gets 744. * $M_B$: $B6 = 1023+745 = 1768$. * New Pending: $P = \{(C9, 838), (C4, 1002), (C7, 1020+744=1764)\}$. **Step 69:** Process (C9, 838). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 419$. Remainder $R = 0$. * B9 gets 419. C10 gets 419. * $M_B$: $B9 = 435+419 = 854$. * New Pending: $P = \{(C4, 1002), (C7, 1764), (C10, 432+419=851)\}$. **Step 70:** Process (C4, 1002). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 334$. Remainder $R = 0$. * B4 gets 334. C2 gets 334. C5 gets 334. * $M_B$: $B4 = 558+334 = 892$. * New Pending: $P = \{(C7, 1764), (C2, 555+334=889), (C5, 1266+334=1600)\}$. **Step 71:** Process (C7, 1764). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 588$. Remainder $R = 0$. * B7 gets 588. C5 gets 588. C8 gets 588. * $M_B$: $B7 = 783+588 = 1371$. * New Pending: $P = \{(C2, 889), (C5, 1600+588=2188), (C8, 777+588=1365)\}$. **Step 72:** Process (C2, 889). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 444$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 445. C3 gets 444. * $M_B$: $B2 = 754+445 = 1199$. * New Pending: $P = \{(C5, 2188), (C8, 1365), (C3, 749+444=1193)\}$. **Step 73:** Process (C5, 2188). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 1094$. Remainder $R = 0$. * B5 gets 1094. C6 gets 1094. * $M_B$: $B5 = 1494+1094 = 2588$. * New Pending: $P = \{(C8, 1365), (C3, 1193), (C6, 1489+1094=2583)\}$. **Step 74:** Process (C8, 1365). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 682$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 683. C9 gets 682. * $M_B$: $B8 = 842+683 = 1525$. * New Pending: $P = \{(C3, 1193), (C6, 2583), (C9, 838+682=1520)\}$. **Step 75:** Process (C3, 1193). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 596$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 597. C4 gets 596. * $M_B$: $B3 = 1015+597 = 1612$. * New Pending: $P = \{(C6, 2583), (C9, 1520), (C4, 1002+596=1598)\}$. **Step 76:** Process (C6, 2583). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 1291$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 1292. C7 gets 1291. * $M_B$: $B6 = 1768+1292 = 3060$. * New Pending: $P = \{(C9, 1520), (C4, 1598), (C7, 1764+1291=3055)\}$. **Step 77:** Process (C9, 1520). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 760$. Remainder $R = 0$. * B9 gets 760. C10 gets 760. * $M_B$: $B9 = 854+760 = 1614$. * New Pending: $P = \{(C4, 1598), (C7, 3055), (C10, 851+760=1611)\}$. **Step 78:** Process (C4, 1598). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 532$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 533. C2 gets 533. C5 gets 532. * $M_B$: $B4 = 892+533 = 1425$. * New Pending: $P = \{(C7, 3055), (C2, 889+533=1422), (C5, 2188+532=2720)\}$. **Step 79:** Process (C7, 3055). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 1018$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 1019. C5 gets 1018. C8 gets 1018. * $M_B$: $B7 = 1371+1019 = 2390$. * New Pending: $P = \{(C2, 1422), (C5, 2720+1018=3738), (C8, 1365+1018=2383)\}$. **Step 80:** Process (C2, 1422). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 711$. Remainder $R = 0$. * B2 gets 711. C3 gets 711. * $M_B$: $B2 = 1199+711 = 1910$. * New Pending: $P = \{(C5, 3738), (C8, 2383), (C3, 1193+711=1904)\}$. **Step 81:** Process (C5, 3738). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 1869$. Remainder $R = 0$. * B5 gets 1869. C6 gets 1869. * $M_B$: $B5 = 2588+1869 = 4457$. * New Pending: $P = \{(C8, 2383), (C3, 1904), (C6, 2583+1869=4452)\}$. **Step 82:** Process (C8, 2383). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 1191$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 1192. C9 gets 1191. * $M_B$: $B8 = 1525+1192 = 2717$. * New Pending: $P = \{(C3, 1904), (C6, 4452), (C9, 1520+1191=2711)\}$. **Step 83:** Process (C3, 1904). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 952$. Remainder $R = 0$. * B3 gets 952. C4 gets 952. * $M_B$: $B3 = 1612+952 = 2564$. * New Pending: $P = \{(C6, 4452), (C9, 2711), (C4, 1598+952=2550)\}$. **Step 84:** Process (C6, 4452). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 2226$. Remainder $R = 0$. * B6 gets 2226. C7 gets 2226. * $M_B$: $B6 = 3060+2226 = 5286$. * New Pending: $P = \{(C9, 2711), (C4, 2550), (C7, 3055+2226=5281)\}$. **Step 85:** Process (C9, 2711). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 1355$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 1356. C10 gets 1355. * $M_B$: $B9 = 1614+1356 = 2970$. * New Pending: $P = \{(C4, 2550), (C7, 5281), (C10, 1611+1355=2966)\}$. **Step 86:** Process (C4, 2550). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 850$. Remainder $R = 0$. * B4 gets 850. C2 gets 850. C5 gets 850. * $M_B$: $B4 = 1425+850 = 2275$. * New Pending: $P = \{(C7, 5281), (C2, 1422+850=2272), (C5, 3738+850=4588)\}$. **Step 87:** Process (C7, 5281). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 1760$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 1761. C5 gets 1760. C8 gets 1760. * $M_B$: $B7 = 2390+1761 = 4151$. * New Pending: $P = \{(C2, 2272), (C5, 4588+1760=6348), (C8, 2383+1760=4143)\}$. **Step 88:** Process (C2, 2272). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 1136$. Remainder $R = 0$. * B2 gets 1136. C3 gets 1136. * $M_B$: $B2 = 1910+1136 = 3046$. * New Pending: $P = \{(C5, 6348), (C8, 4143), (C3, 1904+1136=3040)\}$. **Step 89:** Process (C5, 6348). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 3174$. Remainder $R = 0$. * B5 gets 3174. C6 gets 3174. * $M_B$: $B5 = 4457+3174 = 7631$. * New Pending: $P = \{(C8, 4143), (C3, 3040), (C6, 4452+3174=7626)\}$. **Step 90:** Process (C8, 4143). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 2071$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 2072. C9 gets 2071. * $M_B$: $B8 = 2717+2072 = 4789$. * New Pending: $P = \{(C3, 3040), (C6, 7626), (C9, 2711+2071=4782)\}$. **Step 91:** Process (C3, 3040). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 1520$. Remainder $R = 0$. * B3 gets 1520. C4 gets 1520. * $M_B$: $B3 = 2564+1520 = 4084$. * New Pending: $P = \{(C6, 7626), (C9, 4782), (C4, 2550+1520=4070)\}$. **Step 92:** Process (C6, 7626). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 3813$. Remainder $R = 0$. * B6 gets 3813. C7 gets 3813. * $M_B$: $B6 = 5286+3813 = 9099$. * New Pending: $P = \{(C9, 4782), (C4, 4070), (C7, 5281+3813=9094)\}$. **Step 93:** Process (C9, 4782). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 2391$. Remainder $R = 0$. * B9 gets 2391. C10 gets 2391. * $M_B$: $B9 = 2970+2391 = 5361$. * New Pending: $P = \{(C4, 4070), (C7, 9094), (C10, 2966+2391=5357)\}$. **Step 94:** Process (C4, 4070). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 1356$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 1357. C2 gets 1357. C5 gets 1356. * $M_B$: $B4 = 2275+1357 = 3632$. * New Pending: $P = \{(C7, 9094), (C2, 2272+1357=3629), (C5, 6348+1356=7704)\}$. **Step 95:** Process (C7, 9094). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 3031$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 3032. C5 gets 3031. C8 gets 3031. * $M_B$: $B7 = 4151+3032 = 7183$. * New Pending: $P = \{(C2, 3629), (C5, 7704+3031=10735), (C8, 4143+3031=7174)\}$. **Step 96:** Process (C2, 3629). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 1814$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 1815. C3 gets 1814. * $M_B$: $B2 = 3046+1815 = 4861$. * New Pending: $P = \{(C5, 10735), (C8, 7174), (C3, 3040+1814=4854)\}$. **Step 97:** Process (C5, 10735). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 5367$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 5368. C6 gets 5367. * $M_B$: $B5 = 7631+5368 = 13000 - 1 = 12999$. * New Pending: $P = \{(C8, 7174), (C3, 4854), (C6, 7626+5367=12993)\}$. **Step 98:** Process (C8, 7174). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 3587$. Remainder $R = 0$. * B8 gets 3587. C9 gets 3587. * $M_B$: $B8 = 4789+3587 = 8376$. * New Pending: $P = \{(C3, 4854), (C6, 12993), (C9, 4782+3587=8369)\}$. **Step 99:** Process (C3, 4854). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 2427$. Remainder $R = 0$. * B3 gets 2427. C4 gets 2427. * $M_B$: $B3 = 4084+2427 = 5011$. * New Pending: $P = \{(C6, 12993), (C9, 8369), (C4, 4070+2427=6497)\}$. **Step 100:** Process (C6, 12993). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 6496$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 6497. C7 gets 6496. * $M_B$: $B6 = 9099+6497 = 15596$. * New Pending: $P = \{(C9, 8369), (C4, 6497), (C7, 9094+6496=15590)\}$. **Step 101:** Process (C9, 8369). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 4184$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 4185. C10 gets 4184. * $M_B$: $B9 = 5361+4185 = 9546$. * New Pending: $P = \{(C4, 6497), (C7, 15590), (C10, 5357+4184=9541)\}$. **Step 102:** Process (C4, 6497). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 2165$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 2166. C2 gets 2166. C5 gets 2165. * $M_B$: $B4 = 3632+2166 = 5798$. * New Pending: $P = \{(C7, 15590), (C2, 3629+2166=5795), (C5, 10735+2165=12900)\}$. **Step 103:** Process (C7, 15590). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 5196$. Remainder $R = 2$. * Tie-break order: B7, C5, C8. * B7 gets 5197. C5 gets 5197. C8 gets 5196. * $M_B$: $B7 = 7183+5197 = 12380$. * New Pending: $P = \{(C2, 5795), (C5, 12900+5197=18097), (C8, 7174+5196=12370)\}$. **Step 104:** Process (C2, 5795). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 2897$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 2898. C3 gets 2897. * $M_B$: $B2 = 4861+2898 = 7759$. * New Pending: $P = \{(C5, 18097), (C8, 12370), (C3, 4854+2897=7751)\}$. **Step 105:** Process (C5, 18097). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 9048$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 9049. C6 gets 9048. * $M_B$: $B5 = 12999+9049 = 22048$. * New Pending: $P = \{(C8, 12370), (C3, 7751), (C6, 12993+9048=22041)\}$. **Step 106:** Process (C8, 12370). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 6185$. Remainder $R = 0$. * B8 gets 6185. C9 gets 6185. * $M_B$: $B8 = 8376+6185 = 14561$. * New Pending: $P = \{(C3, 7751), (C6, 22041), (C9, 8369+6185=14554)\}$. **Step 107:** Process (C3, 7751). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 3875$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 3876. C4 gets 3875. * $M_B$: $B3 = 5011+3876 = 8887$. * New Pending: $P = \{(C6, 22041), (C9, 14554), (C4, 6497+3875=10372)\}$. **Step 108:** Process (C6, 22041). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 11020$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 11021. C7 gets 11020. * $M_B$: $B6 = 15596+11021 = 26617$. * New Pending: $P = \{(C9, 14554), (C4, 10372), (C7, 15590+11020=26610)\}$. **Step 109:** Process (C9, 14554). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 7277$. Remainder $R = 0$. * B9 gets 7277. C10 gets 7277. * $M_B$: $B9 = 9546+7277 = 16823$. * New Pending: $P = \{(C4, 10372), (C7, 26610), (C10, 9541+7277=16818)\}$. **Step 110:** Process (C4, 10372). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 3457$. Remainder $R = 1$. * Tie-break order: B4, C2, C5. * B4 gets 3458. C2 gets 3457. C5 gets 3457. * $M_B$: $B4 = 5798+3458 = 9256$. * New Pending: $P = \{(C7, 26610), (C2, 5795+3457=9252), (C5, 18097+3457=21554)\}$. **Step 111:** Process (C7, 26610). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 8870$. Remainder $R = 0$. * B7 gets 8870. C5 gets 8870. C8 gets 8870. * $M_B$: $B7 = 12380+8870 = 21250$. * New Pending: $P = \{(C2, 9252), (C5, 21554+8870=30424), (C8, 12370+8870=21240)\}$. **Step 112:** Process (C2, 9252). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 4626$. Remainder $R = 0$. * B2 gets 4626. C3 gets 4626. * $M_B$: $B2 = 7759+4626 = 12385$. * New Pending: $P = \{(C5, 30424), (C8, 21240), (C3, 7751+4626=12377)\}$. **Step 113:** Process (C5, 30424). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 15212$. Remainder $R = 0$. * B5 gets 15212. C6 gets 15212. * $M_B$: $B5 = 22048+15212 = 37260$. * New Pending: $P = \{(C8, 21240), (C3, 12377), (C6, 22041+15212=37253)\}$. **Step 114:** Process (C8, 21240). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 10620$. Remainder $R = 0$. * B8 gets 10620. C9 gets 10620. * $M_B$: $B8 = 14561+10620 = 25181$. * New Pending: $P = \{(C3, 12377), (C6, 37253), (C9, 14554+10620=25174)\}$. **Step 115:** Process (C3, 12377). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 6188$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 6189. C4 gets 6188. * $M_B$: $B3 = 8887+6189 = 15076$. * New Pending: $P = \{(C6, 37253), (C9, 25174), (C4, 10372+6188=16560)\}$. **Step 116:** Process (C6, 37253). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 18626$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 18627. C7 gets 18626. * $M_B$: $B6 = 26617+18627 = 45244$. * New Pending: $P = \{(C9, 25174), (C4, 16560), (C7, 26610+18626=45236)\}$. **Step 117:** Process (C9, 25174). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 12587$. Remainder $R = 0$. * B9 gets 12587. C10 gets 12587. * $M_B$: $B9 = 16823+12587 = 29410$. * New Pending: $P = \{(C4, 16560), (C7, 45236), (C10, 16818+12587=29405)\}$. **Step 118:** Process (C4, 16560). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 5520$. Remainder $R = 0$. * B4 gets 5520. C2 gets 5520. C5 gets 5520. * $M_B$: $B4 = 9256+5520 = 14776$. * New Pending: $P = \{(C7, 45236), (C2, 9252+5520=14772), (C5, 30424+5520=35944)\}$. **Step 119:** Process (C7, 45236). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 15078$. Remainder $R = 2$. * Tie-break order: B7, C5, C8. * B7 gets 15079. C5 gets 15079. C8 gets 15078. * $M_B$: $B7 = 21250+15079 = 36329$. * New Pending: $P = \{(C2, 14772), (C5, 35944+15079=51023), (C8, 21240+15078=36318)\}$. **Step 120:** Process (C2, 14772). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 7386$. Remainder $R = 0$. * B2 gets 7386. C3 gets 7386. * $M_B$: $B2 = 12385+7386 = 19771$. * New Pending: $P = \{(C5, 51023), (C8, 36318), (C3, 12377+7386=19763)\}$. **Step 121:** Process (C5, 51023). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 25511$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 25512. C6 gets 25511. * $M_B$: $B5 = 37260+25512 = 62772$. * New Pending: $P = \{(C8, 36318), (C3, 19763), (C6, 37253+25511=62764)\}$. **Step 122:** Process (C8, 36318). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 18159$. Remainder $R = 0$. * B8 gets 18159. C9 gets 18159. * $M_B$: $B8 = 25181+18159 = 43340$. * New Pending: $P = \{(C3, 19763), (C6, 62764), (C9, 25174+18159=43333)\}$. **Step 123:** Process (C3, 19763). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 9881$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 9882. C4 gets 9881. * $M_B$: $B3 = 15076+9882 = 24958$. * New Pending: $P = \{(C6, 62764), (C9, 43333), (C4, 16560+9881=26441)\}$. **Step 124:** Process (C6, 62764). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 31382$. Remainder $R = 0$. * B6 gets 31382. C7 gets 31382. * $M_B$: $B6 = 45244+31382 = 76626$. * New Pending: $P = \{(C9, 43333), (C4, 26441), (C7, 45236+31382=76618)\}$. **Step 125:** Process (C9, 43333). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 21666$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 21667. C10 gets 21666. * $M_B$: $B9 = 29410+21667 = 51077$. * New Pending: $P = \{(C4, 26441), (C7, 76618), (C10, 29405+21666=51071)\}$. **Step 126:** Process (C4, 26441). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 8813$. Remainder $R = 2$. * Tie-break order: B4, C2, C5. * B4 gets 8814. C2 gets 8814. C5 gets 8813. * $M_B$: $B4 = 14776+8814 = 23590$. * New Pending: $P = \{(C7, 76618), (C2, 14772+8814=23586), (C5, 51023+8813=59836)\}$. **Step 127:** Process (C7, 76618). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 25539$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 25540. C5 gets 25539. C8 gets 25539. * $M_B$: $B7 = 36329+25540 = 61869$. * New Pending: $P = \{(C2, 23586), (C5, 59836+25539=85375), (C8, 36318+25539=61857)\}$. **Step 128:** Process (C2, 23586). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 11793$. Remainder $R = 0$. * B2 gets 11793. C3 gets 11793. * $M_B$: $B2 = 19771+11793 = 31564$. * New Pending: $P = \{(C5, 85375), (C8, 61857), (C3, 19763+11793=31556)\}$. **Step 129:** Process (C5, 85375). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 42687$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 42688. C6 gets 42687. * $M_B$: $B5 = 62772+42688 = 105460$. * New Pending: $P = \{(C8, 61857), (C3, 31556), (C6, 62764+42687=105451)\}$. **Step 130:** Process (C8, 61857). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 30928$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 30929. C9 gets 30928. * $M_B$: $B8 = 43340+30929 = 74269$. * New Pending: $P = \{(C3, 31556), (C6, 105451), (C9, 43333+30928=74261)\}$. **Step 131:** Process (C3, 31556). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 15778$. Remainder $R = 0$. * B3 gets 15778. C4 gets 15778. * $M_B$: $B3 = 24958+15778 = 40736$. * New Pending: $P = \{(C6, 105451), (C9, 74261), (C4, 26441+15778=42219)\}$. **Step 132:** Process (C6, 105451). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 52725$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 52726. C7 gets 52725. * $M_B$: $B6 = 76626+52726 = 129352$. * New Pending: $P = \{(C9, 74261), (C4, 42219), (C7, 76618+52725=129343)\}$. **Step 133:** Process (C9, 74261). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 37130$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 37131. C10 gets 37130. * $M_B$: $B9 = 51077+37131 = 88208$. * New Pending: $P = \{(C4, 42219), (C7, 129343), (C10, 51071+37130=88201)\}$. **Step 134:** Process (C4, 42219). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 14073$. Remainder $R = 0$. * B4 gets 14073. C2 gets 14073. C5 gets 14073. * $M_B$: $B4 = 23590+14073 = 37663$. * New Pending: $P = \{(C7, 129343), (C2, 23586+14073=37659), (C5, 85375+14073=99448)\}$. **Step 135:** Process (C7, 129343). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 43114$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 43115. C5 gets 43114. C8 gets 43114. * $M_B$: $B7 = 61869+43115 = 104984$. * New Pending: $P = \{(C2, 37659), (C5, 99448+43114=142562), (C8, 61857+43114=104971)\}$. **Step 136:** Process (C2, 37659). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 18829$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 18830. C3 gets 18829. * $M_B$: $B2 = 31564+18830 = 50394$. * New Pending: $P = \{(C5, 142562), (C8, 104971), (C3, 31556+18829=50385)\}$. **Step 137:** Process (C5, 142562). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 71281$. Remainder $R = 0$. * B5 gets 71281. C6 gets 71281. * $M_B$: $B5 = 105460+71281 = 176741$. * New Pending: $P = \{(C8, 104971), (C3, 50385), (C6, 105451+71281=176732)\}$. **Step 138:** Process (C8, 104971). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 52485$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 52486. C9 gets 52485. * $M_B$: $B8 = 74269+52486 = 126755$. * New Pending: $P = \{(C3, 50385), (C6, 176732), (C9, 74261+52485=126746)\}$. **Step 139:** Process (C3, 50385). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 25192$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 25193. C4 gets 25192. * $M_B$: $B3 = 40736+25193 = 65929$. * New Pending: $P = \{(C6, 176732), (C9, 126746), (C4, 42219+25192=67411)\}$. **Step 140:** Process (C6, 176732). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 88366$. Remainder $R = 0$. * B6 gets 88366. C7 gets 88366. * $M_B$: $B6 = 129352+88366 = 217718$. * New Pending: $P = \{(C9, 126746), (C4, 67411), (C7, 129343+88366=217709)\}$. **Step 141:** Process (C9, 126746). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 63373$. Remainder $R = 0$. * B9 gets 63373. C10 gets 63373. * $M_B$: $B9 = 88208+63373 = 151581$. * New Pending: $P = \{(C4, 67411), (C7, 217709), (C10, 88201+63373=151574)\}$. **Step 142:** Process (C4, 67411). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 22470$. Remainder $R = 1$. * Tie-break order: B4, C2, C5. * B4 gets 22471. C2 gets 22470. C5 gets 22470. * $M_B$: $B4 = 37663+22471 = 60134$. * New Pending: $P = \{(C7, 217709), (C2, 37659+22470=60129), (C5, 142562+22470=165032)\}$. **Step 143:** Process (C7, 217709). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 72569$. Remainder $R = 2$. * Tie-break order: B7, C5, C8. * B7 gets 72570. C5 gets 72570. C8 gets 72569. * $M_B$: $B7 = 104984+72570 = 177554$. * New Pending: $P = \{(C2, 60129), (C5, 165032+72570=237602), (C8, 104971+72569=177540)\}$. **Step 144:** Process (C2, 60129). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 30064$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 30065. C3 gets 30064. * $M_B$: $B2 = 50394+30065 = 80459$. * New Pending: $P = \{(C5, 237602), (C8, 177540), (C3, 50385+30064=80449)\}$. **Step 145:** Process (C5, 237602). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 118801$. Remainder $R = 0$. * B5 gets 118801. C6 gets 118801. * $M_B$: $B5 = 176741+118801 = 295542$. * New Pending: $P = \{(C8, 177540), (C3, 80449), (C6, 176732+118801=295533)\}$. **Step 146:** Process (C8, 177540). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 88770$. Remainder $R = 0$. * B8 gets 88770. C9 gets 88770. * $M_B$: $B8 = 126755+88770 = 215525$. * New Pending: $P = \{(C3, 80449), (C6, 295533), (C9, 126746+88770=215516)\}$. **Step 147:** Process (C3, 80449). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 40224$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 40225. C4 gets 40224. * $M_B$: $B3 = 65929+40225 = 106154$. * New Pending: $P = \{(C6, 295533), (C9, 215516), (C4, 67411+40224=107635)\}$. **Step 148:** Process (C6, 295533). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 147766$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 147767. C7 gets 147766. * $M_B$: $B6 = 217718+147767 = 365485$. * New Pending: $P = \{(C9, 215516), (C4, 107635), (C7, 217709+147766=365475)\}$. **Step 149:** Process (C9, 215516). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 107758$. Remainder $R = 0$. * B9 gets 107758. C10 gets 107758. * $M_B$: $B9 = 151581+107758 = 259339$. * New Pending: $P = \{(C4, 107635), (C7, 365475), (C10, 151574+107758=259332)\}$. **Step 150:** Process (C4, 107635). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 35878$. Remainder $R = 1$. * Tie-break order: B4, C2, C5. * B4 gets 35879. C2 gets 35878. C5 gets 35878. * $M_B$: $B4 = 60134+35879 = 96013$. * New Pending: $P = \{(C7, 365475), (C2, 60129+35878=96007), (C5, 237602+35878=273480)\}$. **Step 151:** Process (C7, 365475). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 121825$. Remainder $R = 0$. * B7 gets 121825. C5 gets 121825. C8 gets 121825. * $M_B$: $B7 = 177554+121825 = 299379$. * New Pending: $P = \{(C2, 96007), (C5, 273480+121825=395305), (C8, 177540+121825=299365)\}$. **Step 152:** Process (C2, 96007). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 48003$. Remainder $R = 1$. * Tie-break order: B2, C3. * B2 gets 48004. C3 gets 48003. * $M_B$: $B2 = 80459+48004 = 128463$. * New Pending: $P = \{(C5, 395305), (C8, 299365), (C3, 80449+48003=128452)\}$. **Step 153:** Process (C5, 395305). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 197652$. Remainder $R = 1$. * Tie-break order: B5, C6. * B5 gets 197653. C6 gets 197652. * $M_B$: $B5 = 295542+197653 = 493195$. * New Pending: $P = \{(C8, 299365), (C3, 128452), (C6, 295533+197652=493185)\}$. **Step 154:** Process (C8, 299365). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 149682$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 149683. C9 gets 149682. * $M_B$: $B8 = 215525+149683 = 365208$. * New Pending: $P = \{(C3, 128452), (C6, 493185), (C9, 215516+149682=365198)\}$. **Step 155:** Process (C3, 128452). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 64226$. Remainder $R = 0$. * B3 gets 64226. C4 gets 64226. * $M_B$: $B3 = 106154+64226 = 170380$. * New Pending: $P = \{(C6, 493185), (C9, 365198), (C4, 107635+64226=171861)\}$. **Step 156:** Process (C6, 493185). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 246592$. Remainder $R = 1$. * Tie-break order: B6, C7. * B6 gets 246593. C7 gets 246592. * $M_B$: $B6 = 365485+246593 = 612078$. * New Pending: $P = \{(C9, 365198), (C4, 171861), (C7, 365475+246592=612067)\}$. **Step 157:** Process (C9, 365198). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 182599$. Remainder $R = 0$. * B9 gets 182599. C10 gets 182599. * $M_B$: $B9 = 259339+182599 = 441938$. * New Pending: $P = \{(C4, 171861), (C7, 612067), (C10, 259332+182599=441931)\}$. **Step 158:** Process (C4, 171861). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 57287$. Remainder $R = 0$. * B4 gets 57287. C2 gets 57287. C5 gets 57287. * $M_B$: $B4 = 96013+57287 = 153300$. * New Pending: $P = \{(C7, 612067), (C2, 96007+57287=153294), (C5, 395305+57287=452592)\}$. **Step 159:** Process (C7, 612067). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 204022$. Remainder $R = 1$. * Tie-break order: B7, C5, C8. * B7 gets 204023. C5 gets 204022. C8 gets 204022. * $M_B$: $B7 = 299379+204023 = 503402$. * New Pending: $P = \{(C2, 153294), (C5, 452592+204022=656614), (C8, 299365+204022=503387)\}$. **Step 160:** Process (C2, 153294). Recipients $R_2 = \{B2, C3\}$, $|R_2|=2$. * $Q = 76647$. Remainder $R = 0$. * B2 gets 76647. C3 gets 76647. * $M_B$: $B2 = 128463+76647 = 205110$. * New Pending: $P = \{(C5, 656614), (C8, 503387), (C3, 128452+76647=205099)\}$. **Step 161:** Process (C5, 656614). Recipients $R_5 = \{B5, C6\}$, $|R_5|=2$. * $Q = 328307$. Remainder $R = 0$. * B5 gets 328307. C6 gets 328307. * $M_B$: $B5 = 493195+328307 = 821502$. * New Pending: $P = \{(C8, 503387), (C3, 205099), (C6, 493185+328307=821492)\}$. **Step 162:** Process (C8, 503387). Recipients $R_8 = \{B8, C9\}$, $|R_8|=2$. * $Q = 251693$. Remainder $R = 1$. * Tie-break order: B8, C9. * B8 gets 251694. C9 gets 251693. * $M_B$: $B8 = 365208+251694 = 616902$. * New Pending: $P = \{(C3, 205099), (C6, 821492), (C9, 365198+251693=616891)\}$. **Step 163:** Process (C3, 205099). Recipients $R_3 = \{B3, C4\}$, $|R_3|=2$. * $Q = 102549$. Remainder $R = 1$. * Tie-break order: B3, C4. * B3 gets 102550. C4 gets 102549. * $M_B$: $B3 = 170380+102550 = 272930$. * New Pending: $P = \{(C6, 821492), (C9, 616891), (C4, 171861+102549=274410)\}$. **Step 164:** Process (C6, 821492). Recipients $R_6 = \{B6, C7\}$, $|R_6|=2$. * $Q = 410746$. Remainder $R = 0$. * B6 gets 410746. C7 gets 410746. * $M_B$: $B6 = 612078+410746 = 1022824$. * New Pending: $P = \{(C9, 616891), (C4, 274410), (C7, 612067+410746=1022813)\}$. **Step 165:** Process (C9, 616891). Recipients $R_9 = \{B9, C10\}$, $|R_9|=2$. * $Q = 308445$. Remainder $R = 1$. * Tie-break order: B9, C10. * B9 gets 308446. C10 gets 308445. * $M_B$: $B9 = 441938+308446 = 750384$. * New Pending: $P = \{(C4, 274410), (C7, 1022813), (C10, 441931+308445=750376)\}$. **Step 166:** Process (C4, 274410). Recipients $R_4 = \{B4, C2, C5\}$, $|R_4|=3$. * $Q = 91470$. Remainder $R = 0$. * B4 gets 91470. C2 gets 91470. C5 gets 91470. * $M_B$: $B4 = 153300+91470 = 244770$. * New Pending: $P = \{(C7, 1022813), (C2, 153294+91470=244764), (C5, 656614+91470=748084)\}$. **Step 167:** Process (C7, 1022813). Recipients $R_7 = \{B7, C5, C8\}$, $|R_7|=3$. * $Q = 340937$. Remainder $R = 2 INFO 2026-01-18T15:35:38 +26ms service=bus type=message.part.updated publishing INFO 2026-01-18T15:35:38 +1ms service=bus type=message.updated publishing INFO 2026-01-18T15:35:38 +4ms service=bus type=message.updated publishing INFO 2026-01-18T15:35:38 +0ms service=bus type=session.status publishing INFO 2026-01-18T15:35:38 +1ms service=session.prompt step=1 sessionID=ses_42e414dc5ffe0gmayFC7Zdu06B loop INFO 2026-01-18T15:35:38 +3ms service=bus type=message.updated publishing INFO 2026-01-18T15:35:38 +1ms service=bus type=session.updated publishing INFO 2026-01-18T15:35:38 +1ms service=bus type=session.diff publishing INFO 2026-01-18T15:35:38 +1ms service=session.prompt sessionID=ses_42e414dc5ffe0gmayFC7Zdu06B exiting loop INFO 2026-01-18T15:35:38 +0ms service=session.compaction pruning INFO 2026-01-18T15:35:38 +3ms service=session.prompt sessionID=ses_42e414dc5ffe0gmayFC7Zdu06B cancel INFO 2026-01-18T15:35:38 +1ms service=bus type=session.status publishing INFO 2026-01-18T15:35:38 +0ms service=bus type=session.idle publishing INFO 2026-01-18T15:35:38 +2ms service=default directory=/app/input disposing instance INFO 2026-01-18T15:35:38 +1ms service=state key=/app/input waiting for state disposal to complete INFO 2026-01-18T15:35:38 +1ms service=state key=/app/input state disposal completed --- Initial command finished (exit code: 0) --- --- no_shell=true, exiting container without starting shell --- Command execution complete. Container has exited. Session has been cleaned up.